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x^2-27x-810=0
a = 1; b = -27; c = -810;
Δ = b2-4ac
Δ = -272-4·1·(-810)
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3969}=63$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-63}{2*1}=\frac{-36}{2} =-18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+63}{2*1}=\frac{90}{2} =45 $
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